Find the adjoint of matrix A- - aij - 1 1 1- 2 1 -3- -1 2 3 - and evaluate the answer

Ad joint of matrix=Transpose of co factor matrix C _ 11 = 1 amp; 3 2 amp; 3 =9 C _ 12 = 2 amp; 3 1 amp; 3 = 3, C _ 23 = 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Adjoint of a Matrix

Find the adjo...

Question

Find the adjoint of matrix $A = [a_{i j}] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 2 & 1 & - 3 - 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦$ and evaluate the answer

Open in App

Solution

Suggest Corrections

Similar questions

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 2 & 1 & - 3 - 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 2 & 1 & - 3 - 1 & 2 & 3 \end{matrix} ⎤ ⎥ ⎦

= ⎛ ⎜ ⎝ \begin{matrix} 2 & 5 & 3 3 & 1 & 2 1 & 2 & 1 \end{matrix} ⎞ ⎟ ⎠

[A_{i j}] = ⎡ ⎢ ⎣ \begin{matrix} - 3 & - 1 & 5 1 & - 1 & 1 7 & 5 & - 13 \end{matrix} ⎤ ⎥ ⎦ a d j A = {[A_{i j}]}^{T}

[a i j]_{3 \times 2},

a i j = (3 i - 2 j)^{2}

A = ⎡ ⎢ ⎣ \begin{matrix} 3 & - 3 & 4 2 & - 3 & 4 0 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦

Join BYJU'S Learning Program