Find the alkyne among all the other alkanes in the given options.

$C_{3} H_{8}$

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$C_{4} H_{6}$

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$C_{5} H_{12}$

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$C H_{4}$

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Solution

The correct option is B
$C_{4} H_{6}$

An alkyne is a hydrocarbon in which at least two carbon atoms are joint to each other by a triple bond.

The general formula for alkyne is $C_{n} H_{2 n - 2}$ . So if you put the value of $n$ equal to the number of carbon atoms in the given options we will know which option is the correct one.

For $n = 1$
$C_{1} H_{2 \times 1 - 2}$ = $C_{1} H_{0}$ This compound is not possible as this is only a carbon atom.

For $n = 3$ ,
$C_{3} H_{2 \times 3 - 2}$ = $C_{3} H_{4}$ This is not equal to $C_{3} H_{8}$

For $n = 4$ ,
$C_{4} H_{2 \times 4 - 2}$ = $C_{4} H_{6}$ This is equal to $C_{4} H_{6}$

For $n = 5$
$C_{5} H_{2 \times 5 - 2}$ = $C_{5} H_{8}$ This is not equal to $C_{5} H_{12}$

So amond the given options $C_{4} H_{6}$ is the only alkyne among the given options.

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