Question

Find the altitude of a trapezium whose area is 65 $c{m}^2$ and whose bases are 13 cm and 26 cm.

Answer 1

Area of a trapezium= 65 $c{m}^2$

Bases are 13 cm and 26 cm i.e.,$\left(b_1\right)=13cm,b_2=26cm$

$=Height\left(h\right)=\frac{Area\times 2}{Sumofbases}=\frac{65\times 2}{(13+26)}=\frac{65\times 2}{39}=\frac{10}{3}cm$