Question

Find the altitude of a trapezium whose area is 65 cm² and whose bases are 13 cm and 26 cm.

Answer 1

$$\begin{gathered} \text{Given:} \\ {\text{Area of the trapezium=65 cm}}^2 \\ \text{The lengths of the opposite parallel sides are 13 cm and 26 cm.} \\ \text{Area of trapezium=}\frac{1}{2}\text{×(Sum of parallel bases)×(Altitude)} \\ \mathrm{On}\mathrm{puttin}g\mathrm{the}\mathrm{values}: \\ 65=\frac{1}{2}\times (13+26)\times (\text{Altitude)} \\ 65\times 2=39\times \text{Altitude} \\ \text{Altitude=}\frac{130}{39}\text{=}\frac{10}{3}\text{cm} \end{gathered}$$