Question

Find the altitude of a triangle whose area is 42 cm² and base is 12 cm.

Answer 1

We have,
Altitude of a triangle = $\frac{2\times \mathrm{Area}}{\mathrm{Base}}$
Here, base = 12 cm and area = 42 cm²

∴ Altitude = $\frac{2\times 42}{12}=7\mathrm{cm}$