Question

Find the altitude of a triangle whose area is $784$ sq.cm and base is $32$ cm

Answer 1

Area of a triangle$=\frac{1}{2}\times base\times height$

$\Rightarrow 784=\frac{1}{2}\times 32\times height$

$\Rightarrow height=\frac{784\times 2}{32}=49cm$

Hence altitude of the triangle is $49cm$