Find the amount and compound interest on $R s . 2500$ for $2$ years at $10$ % per annum compounded annually.

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Solution

$A = P (1 + \frac{r}{100})^{n}$
$A = 2500 = (1 + \frac{10}{100})^{2} = 2500 (\frac{110}{100})^{2} = 2500 \times \frac{11}{10} \times \frac{11}{10}$
$= 25 \times 11 \times 11 = 3025$
$∴ A = R s 3025$

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Find the amount and compound interest on Rs. 2500 for 2 years at 10% per annum compounded annually.

A=P(1+r100)nA=2500=(1+10100)2=2500(110100)2=2500×1110×1110=25×11×11=3025∴A=Rs3025

Find the amount and compound interest on $R s . 2500$ for $2$ years at $10$ % per annum compounded annually.

$A = P (1 + \frac{r}{100})^{n}$
$A = 2500 = (1 + \frac{10}{100})^{2} = 2500 (\frac{110}{100})^{2} = 2500 \times \frac{11}{10} \times \frac{11}{10}$
$= 25 \times 11 \times 11 = 3025$
$∴ A = R s 3025$