Find the amount and the compound interest on Rs. 10000 in 3 years, if the rate of interest for the successive years are 10%, 15% and 20% respectively.

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Solution

Principal(P)=Rs. 10000
Time(t)=3 years
Rate( $R_{1}$ )=10%
Rate( $R_{2}$ )=15%
Rate( $R_{3}$ )=20%
Amount= $P (1 + \frac{R_{1}}{100}) (1 + \frac{R_{2}}{100}) (1 + \frac{R_{3}}{100})$
$= R s . 10000 \times (1 + \frac{10}{100}) (1 + \frac{15}{100}) (1 + \frac{20}{100})$
$= R s . 10000 \times \frac{11}{10} \times \frac{23}{20} \times \frac{6}{5} = R s . 15180$
C.I.=Amount-Principal
=Rs. 15180-Rs. 10000=Rs. 5180

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Find the amount and the compound interest on Rs. 10000 in 3 years, if the rate of interest for the successive years are 10%, 15% and 20% respectively.

Principal(P)=Rs. 10000 Time(t)=3 years Rate(R1)=10% Rate(R2)=15% Rate(R3)=20% Amount= P(1+R1100)(1+R2100)(1+R3100) =Rs.10000×(1+10100)(1+15100)(1+20100) =Rs.10000×1110×2320×65=Rs.15180 C.I.=Amount-Principal =Rs. 15180-Rs. 10000=Rs. 5180