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Byju's Answer
Standard XII
Chemistry
Normality
Find the amou...
Question
Find the amount of
98
%
pure
N
a
2
C
O
3
required to prepare 5 litres of 2 N solution.
A
54.8 g impure
N
a
2
C
O
3
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B
540.8 g impure
N
a
2
C
O
3
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C
40.8 g impure
N
a
2
C
O
3
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D
340.8 g impure
N
a
2
C
O
3
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Solution
The correct option is
B
540.8 g impure
N
a
2
C
O
3
no. of equivalents = normality
×
volume
=5
×
2
=10
Also, no. of equivalents =
w
e
i
g
h
t
e
q
u
i
v
a
l
e
n
t
w
e
i
g
h
t
Therefore,
w
e
i
g
h
t
×
2
m
o
l
e
c
u
l
a
r
w
e
i
g
h
t
=10....... [n factor for Na
2
C
O
3
=2]
Weight =5x molecular weight = 5x 106 =530
Sample is 98% pure
amount required =
530
×
100
98
=540.8g impure Na
2
C
O
3
Suggest Corrections
0
Similar questions
Q.
21.2
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N
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3
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, the weight of
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Q.
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Q.
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6.2
g of a sample containing
N
a
2
C
O
3
,
N
a
H
C
O
3
and non-volatile inert impurity on gentle heating loses
5
%
of its weight due to reaction:
2
N
a
H
C
O
3
→
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3
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