Find the amount of potassium chlorate subjected to thermal decomposition to give oxygen which was sufficient for the combustion of $120 g o f e t h a n e (C_{2} H_{6})$ .

9.3 moles

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4.6 moles

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3.9 moles

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2.2 moles

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Solution

The correct option is A 9.3 moles
$2 K C l O_{3} \to 2 K C l + 3 O_{2}$
$C_{2} H_{6} + \frac{7}{2} O_{2} \to 2 C O_{2} + 3 H_{2} O$
$120 g C_{2} H_{6} \to 4 m o l e s o f C_{2} H_{6}$
$1 m o l e C_{2} H_{6} r e q u i r e s \frac{7}{2} m o l e s O_{2}$
$4 m o e l s C_{2} H_{6} r e q u i r e s = 4 \times \frac{7}{2} = 14 m o l e s O_{2}$
$3 m o l e s O_{2} \to 2 m o l e s K C l O_{3}$
$14 m o l e s O_{2} \to \frac{2 \times 14}{3} = 9.3 m o l e s o f K C l O_{3}$

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C_{2} H_{6}

(K C l O_{3})

(K C l)

(O_{2})

K C l O_{3}

O_{2}

Which compound is used as a catalyst in the process of decomposition of potassium chlorate to prepare oxygen?

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