Question

Find the amount of water displaced by a solid spherical ball of diameter
(i) $28cm$
(ii) $0.21m$

Answer 1

Amount of water disploud by a solid phurical ball a equal to its volume

$\Rightarrow \frac{4}{3}\pi r^3$; where ${}^{\prime }{r}^{\prime }$ is radius of the ball.

$\left(i\right)28cm$

$\therefore d=28cm,$ radius $=\frac{d}{2}=\frac{28}{2}=14cm$

$\therefore$ Volume $=\frac{4}{3}\times \pi r^3=\frac{4}{3}\times \pi \times 14\times 14\times 14=11498.66c{m}^3$

$\left(ii\right)0.21m=21cm$

$\therefore d=21cm$; radius $=\frac{d}{2}=\frac{21}{2}cm$

Volume $=\frac{4}{3}\times \pi \times r^3=\frac{4}{3}\times \pi \times \frac{21}{2}\times \frac{21}{2}\times \frac{21}{2}=4846.59c{m}^3$