Find the amount on ₹ 40,000 in 2 years, when the rates of interest for two successive years are 14 % and 12 % successively.
₹ 51,072
P = ₹ 40,000 T = 2 years , R1 = 14 % and R2 = 12 %
A = P(1+R1100)(1+R2100)
= 40,000(1+14100)(1+12100)
= 40,000(114100)(112100)
= ₹ 51,072