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Global Maxima

Find the ampl...

Question

Find the amplitude (in cm) of a particle due to superposition of two S.H.M. along the same line.

$x_{1} = 5 s i n (t - 37^{o})$

$x_{2} = 6 c o s t$

$\sqrt{61}$

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$\sqrt{97}$

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$\sqrt{109}$

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$5$

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Solution

The correct option is D
$5$

$x_{1} = 5 s i n (t - 37^{o})$

$x_{2} = 6 s i n (t + 90^{o})$

$A = \sqrt{(6 - 3)^{2} + 4^{2}}$

$= 5$

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Similar questions

X_{1} = 2 s i n 50 μ t

X_{2} = 10 s i n (50 π t + 37^{0})

X_{3} = - 4 s i n 50 π t

X_{4} = - 12 c o s 50 π t

x_{1} = 10 s i n (ω t + 30^{\circ}

x_{2}

ω t + 60^{\circ}

x_{1} = 3 sin ω t

x_{2} = 5 sin (ω t + 37^{\circ})

x_{3} = - 15 cos ω t

x_{1} = 3 s i n ω t, x_{2} = 5 s i n (ω t + 37^{\circ})

x_{3} = - 15 c o s ω t

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