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Length of Tangent and Power of a Point

Find the angl...

Question

Find the angle between pair of tangents drawn from (0,0) to the circle x^2+y^2-14x+2y+25=0

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θ

is the angle between the tangents from

(0, 0)

x^{2} + y^{2} - 14 x + 2 y + 25 = 0

sin (\frac{θ}{2}) + cos (\frac{θ}{2}) =

The cosine of the angle between the tangents from the origin to the circle $x^{2} + y^{2} - 14 x + 2 y + 25$ = 0 is

Q. If tangents are drawn from any point on the circle

x^{2} + y^{2} = 25

\frac{x^{2}}{16} + \frac{y^{2}}{9} = 1,

then the angle between the tangents is

Q. Angle between tangents drawn to circle

x^{2} + y^{2} = 20

, from the point

(6, 2)

Q. Angle between pair of tangents drawn from point

(4, 3)

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

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