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Question
Find the angle between planes 2x+y−2z=5 and 3x−6y−2z=7
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Solution
The normal of the two planes can be written as
n1=2i+j−2k and n2=3i−6j−2k
Hence the angle between the planes can be gives as
θ=cos−1(→n1.→n2|n1||n2|)
=cos−1(6−6+4√9×√49)
θ=cos−1(421)
n1=2i+j−2k and n2=3i−6j−2k
Hence the angle between the planes can be gives as
θ=cos−1(→n1.→n2|n1||n2|)
=cos−1(6−6+4√9×√49)
θ=cos−1(421)
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