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Question

Find the angle between the following pairs of lines: (i) (ii)

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Solution

(i)

The pair of lines is given as,

x2 2 = y1 5 = z+3 3

And,

x+2 1 = y4 8 = z5 4

Consider that Q is the angle between the given lines.

The formula to calculate the angle between the pair of lines is,

cosQ=| b 1 b 2 | b 1 || b 2 | |(1)

The given lines are parallel to the vectors,

b 1 =2 i ^ +5 j ^ 3 k ^

And,

b 2 = i ^ +8 j ^ +4 k ^

The value of b 1 is,

b 1 = 2 2 + 5 2 + ( 3 ) 2 = 38

The value of b 2 is,

b 2 = ( 1 ) 2 + 8 2 + 4 2 = 81 =9

The value of b 1 b 2 is,

b 1 b 2 =( 2 i ^ +5 j ^ 3 k ^ )( i ^ +8 j ^ +4 k ^ ) =2×( 1 )+5×8+( 3 )×4 =2+4012 =26

Substitute the values in equation (1),

cosQ=| 26 9 38 | Q= cos 1 ( 26 9 38 )

(ii)

The pair of lines is given as,

x 2 = y 2 = z 1

And,

x5 4 = y2 1 = z3 8

Consider that Q is the angle between the given lines.

The formula to calculate the angle between the pair of lines is,

cosQ=| b 1 b 2 | b 1 || b 2 | |(1)

The given lines are parallel to the vectors,

b 1 =2 i ^ +2 j ^ + k ^

And,

b 2 =4 i ^ + j ^ +8 k ^

The value of b 1 is,

b 1 = 2 2 + ( 2 ) 2 + ( 1 ) 2 = 9 =3

The value of b 2 is,

b 2 = 4 2 + ( 1 ) 2 + ( 8 ) 2 = 81 =9

The value of b 1 b 2 is,

b 1 b 2 =( 2 i ^ +2 j ^ + k ^ )( 4 i ^ + j ^ +8 k ^ ) =2×4+2×( 1 )+1×( 8 ) =8+2+8 =18

Substitute the values in equation (1),

cosQ=| 18 3×9 | cosQ= 2 3 Q= cos 1 ( 2 3 )


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