Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius 4m. If its speed is increasing at 3m/s every second, at an instant when the speed of the particle is 4m/s.
A
37∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
53∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
60∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
45∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B53∘ Let the tangential acceleration be at And centripetal acceleration be ac
Given the speed of the particle is v=4m/s. speed is increasing at 3m/s every second at=dvdt=31=3m/s2
Centripetal acceleration ac=v2R=424=4m/s2
Net acceleration, anet=√a2c+a2t=√42+32=5m/s2 Now angle between net acceleration and tangential acceleration is cosθ=atanet=35 ∴θ=53∘