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Question

Find the angle between the net acceleration vector and tangential acceleration vector for a particle moving in a circle of radius 4 m and its speed is increasing at 3 m/s every second, when the speed of the particle is 4 m/s.

A
37
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B
53
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C
60
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D
45
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Solution

The correct option is B 53
Let the tangential acceleration be at
and centripetal acceleration be ac
ac=v2R=424=4 m/s2
at=3 m/s2
anet=a2c+a2t
=42+32=5 m/s2


Now given that θ is the angle between the net acceleration and tangential acceleration.
Hence,
cosθ=atanet=35
θ=53

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