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Question

Find the angle between the planes
2x+7y+11z3=0 and 5x+3y+9z+1=0


  1. cos1(130174.115)

  2. cos1(139174.115)

  3. cos1(123174.115)

  4. cos1(107174.115)


Solution

The correct option is A

cos1(130174.115)


We know that the angle between two planes a1x+b1y+c1z+d1=0 & a2x+b2y+c2z+d2=0 is given by -

cosθ=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)

So, Here we’ll substitute the appropriate values.

cosθ=2.5+7.3+11.9(22+72+112)(52+32+92)cosθ=130174.115θ=cos1(130174115)

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