Find the angle between the vectors 3i+2j−6k and 4i−3j+k.
Consider the given vectors.
a=3i+2j−6k
b=4i−3j+k
Now,
a⋅b=(3i+2j−6k)(4i−3j+k)
a⋅b=12−6−6=0
Therefore,
Two vectors a and b are perpendicular.
Thus, the angle between the vectors a and b =90∘
Hence, this is the answer.