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Question

Find the angle between the vectors 3i+2j6k and 4i3j+k.

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Solution

Consider the given vectors.

a=3i+2j6k

b=4i3j+k

Now,

ab=(3i+2j6k)(4i3j+k)

ab=1266=0

Therefore,

Two vectors a and b are perpendicular.

Thus, the angle between the vectors a and b =90

Hence, this is the answer.


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