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Question

Find the angle between the vectors whose direction cosines are proportional to 2,3,6 and 3,4,5.

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Solution

Let, θ is the angle between two lines whose direction cosines are,

l1=2,m1=3,n1=6;

l2=3,m2=4,n2=5;

We know that,

cosθ=l1l2+m1m2+n1n2

=2×3+3×(4)6×5

=61230

=36

Therefore,

cosθ=36

θ=cos1(36)

Not possible because 1cosθ1

Hence question is wrong.

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