Find the angle between two vectors and with magnitudes and 2, respectively having .

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Solution

Given vectors are a → and b → , such that a → ⋅ b → = 6 , | a → |= 3 and | b → |=2.

Formula used for dot product is,

a → ⋅ b → =| a → || b → |cosθ

Here, the angle between a → and b → is θ.

Substitute all the values in the above formula.

6 = 3 ×2×cosθ 6 3 ×2 =cosθ cosθ= 1 2 θ= π 4

Thus, the angle between a → and b → is π 4 .

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