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Byju's Answer
Standard XII
Mathematics
Integration Using Substitution
Find the angl...
Question
Find the angle between
→
i
−
→
j
+
→
k
,
−
→
i
+
→
j
+
2
→
k
A
π
2
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B
π
4
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C
π
3
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D
π
6
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Solution
The correct option is
A
π
2
Given vectors are
→
i
−
→
j
+
→
k
and
−
→
i
+
→
j
+
2
→
k
We know,
cos
θ
=
∣
∣ ∣ ∣
∣
a
1
a
2
+
b
1
b
2
+
c
1
c
2
√
(
a
1
)
2
+
(
b
1
)
2
+
(
c
1
)
2
√
(
a
2
)
2
+
(
b
2
)
2
+
(
c
2
)
2
∣
∣ ∣ ∣
∣
=
∣
∣
∣
−
1
−
1
+
2
√
1
+
1
+
1
√
1
+
1
+
4
∣
∣
∣
=
0
∴
θ
=
π
2
Suggest Corrections
0
Similar questions
Q.
A unit vector coplanar with
→
i
+
→
j
+
2
→
k
and
→
i
+
2
→
j
+
→
k
, and perpendicular to
→
i
+
→
j
+
→
k
, is
Q.
If
→
a
=
→
i
+
→
j
+
→
k
,
→
a
=
2
→
i
+
→
k
,
→
c
=
2
→
i
+
→
j
+
→
k
;
→
d
=
→
i
+
→
j
+
2
→
k
, then verify that
(
→
a
×
→
b
)
×
(
→
c
×
→
d
)
=
[
→
a
→
b
→
d
]
→
c
−
[
→
a
→
b
→
c
]
→
d
Q.
Angle between the vectors
(
→
i
+
→
j
)
and
(
→
j
+
→
k
)
is:
Q.
The value of
→
i
×
(
→
a
×
→
i
)
+
→
j
×
(
→
a
×
→
j
)
+
→
k
×
(
→
a
×
→
k
)
is (where
→
i
,
→
j
,
→
k
are unit vectors)
Q.
3
→
i
+3
→
j
+
√
3
→
k
,
→
i
+
→
k
,
√
3
→
i
+
√
3
→
j
+ p
→
k
are coplanar vectors then value of p will be:
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