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Question

Find the angle between ij+k,i+j+2k

A
π2
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B
π4
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C
π3
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D
π6
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Solution

The correct option is A π2
Given vectors are ij+k and i+j+2k
We know, cosθ=∣ ∣ ∣a1a2+b1b2+c1c2(a1)2+(b1)2+(c1)2(a2)2+(b2)2+(c2)2∣ ∣ ∣
=11+21+1+11+1+4=0
θ=π2

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