Question

Find the angle of deviation of the particle as it comes out of the magnetic field if the lateral width $d$ of the region is slightly larger than $\frac{mv}{qB}$.

• A. $\frac{\pi }{4}$
• B. $\frac{\pi }{3}$
• C. $\frac{\pi }{2}$
• D. $\pi$

Answer 1

The correct option is D $\pi$


For the charged particle, $\frac{m{v}^2}{R}=Bqv$

So, $R=\frac{mv}{Bq}$

As $d$ is slightly greater than $R$, therefore, charge will be able to complete a semicircle and turn back to the same side.

So, the angle of deviation will be $\pi$.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, option $\left(D\right)$ is the correct answer.

Why this question? To understand the concept of deflection of a charged particle when it enters a magnetic field.