Question

Find the angle of elevation in degrees of the sun when the shadow of a pole h metres high is $\sqrt{3}h$ meters long.

Answer 1

Let opposite to angle $=$ $h$ ....(pole height)
Adjusted to angle $=$ $h\sqrt{3}$ ....(length of the shadow)
Hence, $\tan \theta =\frac{h}{h\sqrt{3}}$
$\Rightarrow \tan \theta =\frac{1}{\sqrt{3}}$
$\Rightarrow \theta ={30}^{\circ }$