Question

Find the angle of inclination of straight line whose slope is $\frac{1}{\sqrt{3}}$.

Answer 1

We know that if $\theta$ is the inclination of a straight line, then $\tan \theta$ is called the slope (or gradient) of a line. The slope of a line is usually denoted by $m$.

Here, it is given that the slope of the line is $m=\frac{1}{\sqrt{3}}$, therefore, the angle of inclination is:

$m=\tan \theta \Rightarrow \frac{1}{\sqrt{3}}=\tan \theta \Rightarrow \tan {30}^0=\tan \theta (\because \tan {30}^0=\frac{1}{\sqrt{3}})\Rightarrow \theta ={30}^0$

Hence, the angle of inclination is${30}^0$.