Question

Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

Answer 1

$R=\frac{u^{2}sin2\theta }{g}=H=\frac{u^2{sin}^2\theta }{2g}\Rightarrow 2sin\theta cos\theta =\frac{{sin}^2\theta }{2}\Rightarrow tan\theta =4\Rightarrow \theta ={tan}^{-1}\left(4\right)$