Question

Find the angle which exceed its complementary by $30$.

Answer 1

Finding the angle which exceeds its complementary by $30$.

Let us assume that the two angles that add up to $90$ degrees.

We know that, if two angles are complementary, then the sum of their measures is $90$ degrees.

Let $x°$ be the first of the two angles.

So, the second angle is $\left(90-x\right)°$.

From the question, the first angle surpasses its complementary by $30$.

Since, the $2^{nd}$ angle is complementary of the $1^{st}$ angle.

$\Rightarrow$ $x=\left(90-x\right)+30$

$\Rightarrow$ $2x=120$

$\Rightarrow$ $x=60$

Hence, the angle which exceeds its complementary by $30$ is $60°$.