Question

Find the angle which is ${30}^o$ more than its complement.

• A. $50$
• B. $55$
• C. $60$
• D. $65$

Answer 1

The correct option is C $60$

Let the required angle be $x$.

Then, its complement $=({90}^o-x)$.

Given, the angle is ${30}^o$ more than its complement.

Then, $x=({90}^o-x)+{30}^o$

$\Rightarrow x+x={90}^o+{30}^o$

$\Rightarrow 2x={120}^o\Rightarrow x={\frac{120}{2}}^o\Rightarrow x={60}^o$.

Therefore, option $C$ is correct.