Question

Find the angle which is ${60}^o$ more than its complement.

• A. $55$
• B. $75$
• C. $85$
• D. $60$

Answer 1

The correct option is B $75$

Let the required angle be $x$.

Then, its complement $=({90}^o-x)$.

Given, the angle is ${60}^o$ more than its complement.

Then, $x=({90}^o-x)+{60}^o$

$\Rightarrow x+x={90}^o+{60}^o$

$\Rightarrow 2x={150}^o\Rightarrow x={\frac{150}{2}}^o\Rightarrow x={75}^o$.

Therefore, option $B$ is correct.