Question

Find the angle which is ${80}^o$ more than its complement.

• A. $75$
• B. $85$
• C. $95$
• D. $100$

Answer 1

Answer: (B)

$85$

Let the required angle be $x$.

Then, its complement $=({90}^o-x)$.

Given, the angle is ${80}^o$ more than its complement.

Then, $x=({90}^o-x)+{80}^o$

$\Rightarrow x+x={90}^o+{80}^o$

$\Rightarrow 2x={170}^o\Rightarrow x={\frac{170}{2}}^o\Rightarrow x={85}^o$.

Therefore, option $B$ is correct.