Question

Find the angle which is five times its supplement.

Answer 1

Consider the required angle as $x^o$

We know that the complement can be written as ${180}^o-x^o$

To find the measure of an angle is equal to its complement

We get

$x^o=5[{180}^o-x^o]$

We can also write it as

$x=900-5x$

so we get

$6x=900$

By division we get

$x=\frac{900}{2}$

$x^o={150}^o$

Therefore the measure of an angle which is five times than its supplement is ${150}^o$