Find the angle whose supplement is four times its complement.

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Solution

Let the angle be $x$ .
Its supplement is $180 - x$
Its complement is $90 - x$
So, $180 - x = 4 \times (90 - x)$
Or $180 - x = 360 - 4 x$
$⟹ x = \frac{180}{3} = 60^{o}$

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Similar questions

Find the angle whose;

i) Complement is one sixth of its supplement.

ii) Supplement is four times its complement.

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Find the angle whose complement is one third of its supplement.

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