Question

Find the angle x from the figure if ABCD is a parallelogram in which $\angle A:\angle B=1:4$. Also, $\Delta$DEF is an isosceles triangle with DE = DF.

• A. 36°
• B. 54°
• C. 18°
• D. 44°

Answer 1

The correct option is C

18°

As given in question, $\frac{\angle A}{\angle B}$ = $\frac{1}{4}$
$\Rightarrow$ $\angle B$ = 4$\angle A$------------(1)
Also, $\angle A$ + $\angle B$ = 180° (Properties of parallelogram)
From equation (1),$\angle A$ + 4$\angle A$ = 180°
$\Rightarrow$ 5$\angle A$ = 180°
$\Rightarrow$ $\angle A$ = 36°
$\Rightarrow$ $\angle B$ = 4 $\times$ 36° = 144°
In a parallelogram, opposite angles are equal.
So, $\angle B$ = $\angle D$
$\angle D$ = $\angle EDF$ = 144° (Vertically opposite angles)
$\Delta DEF$ is an isosceles triangle.
DE = DF (Given in question)
So, $\angle E$ = $\angle F$
Also, $\angle EDF$ + $\angle E$ + $\angle F$ = 180°
$\Rightarrow$ 144° + x + x = 180°
$\Rightarrow$ 2x = 180° - 144°
$\Rightarrow$ x = $\frac{36°}{2}$ = 18°