Find the angles in each of the following.
Two complementary angles are in the ratio $3 : 2$

54^{\circ}, 36^{\circ}

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44^{\circ}, 36^{\circ}

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54^{\circ}, 46^{\circ}

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None of these

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Solution

The correct option is A $54^{\circ}, 36^{\circ}$
Let the angles be $3 x$ and $2 x$ ,

since both the angles are complementary

So, $2 x + 3 x = 90^{o}$

$=> 5 x = 90^{o}$

$=> x = 18^{o}$

So one angle is $2 x = 2 \times 18^{o} = 36 °$
and other angle is $3 x = 3 \times 18^{o} = 54 °$ .

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Similar questions

Three exterior angles of a hexagen are $40^{\circ}, 51^{\circ}$ and $86^{\circ}$ . If each of the remaining exterior angles are $x^{\circ}$ , then x = ___.

Three exterior angles of a hexagon are $40^{\circ}, 51^{\circ}$ and $86^{\circ}$ . If each of the remaining exterior angles is $x^{\circ}$ , then x=___

Q. Question 31
If two adjacent angles of a parallelogram are in the ratio 2 : 3, then the measures of the angles are
a)

72^{\circ}, 108^{\circ}

36^{\circ}, 54^{\circ}

80^{\circ}, 120^{\circ}

96^{\circ}, 144^{\circ}

Q. Two complementary angles are such that twice the measure of one is equal to three times the measure of the other. The measure of larger angle is
(a) 72°
(b) 54°
(c) 63°
(d) 36°

Question 54

Fill in the blanks to make the statement true.

In a pair of complementary angles, each angle cannot be more than ___ .

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Find the angles in each of the following.Two complementary angles are in the ratio 3:2

The correct option is A 54∘,36∘Let the angles be 3x and 2x ,since both the angles are complementarySo, 2x+3x=90o=>5x=90o=>x=18oSo one angle is 2x=2×18o=36°and other angle is 3x=3×18o=54°.

Find the angles in each of the following.
Two complementary angles are in the ratio $3 : 2$

The correct option is A $54^{\circ}, 36^{\circ}$
Let the angles be $3 x$ and $2 x$ ,

since both the angles are complementary

So, $2 x + 3 x = 90^{o}$

$=> 5 x = 90^{o}$

$=> x = 18^{o}$

So one angle is $2 x = 2 \times 18^{o} = 36 °$
and other angle is $3 x = 3 \times 18^{o} = 54 °$ .