Question

Find the angles of inclination of straight lines whose slopes are $\sqrt{3}$.

Answer 1

We know that if $\theta$ is the inclination of a straight line, then $\tan \theta$ is called the slope (or gradient) of a line. The slope of a line is usually denoted by $m$.

Here, it is given that the slope of the line is $m=\sqrt{3}$, therefore, the angle of inclination is:

$m=\tan \theta \Rightarrow \sqrt{3}=\tan \theta \Rightarrow \tan {60}^0=\tan \theta (\because \tan {60}^0=\sqrt{3})\Rightarrow \theta ={60}^0$

Hence, the angle of inclination is${60}^0$.