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Question

Find the angles of quadrilateral ABCD, in given figure.


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Solution

AB = BD (in ADB)
1=70 1+70+2=180 (Angles sum property of triangle) 70+70+2=180 2=18014040Also inDCBDC=CB 3=4=y y+y+80=180(Assume sum property of triangle) 2y=18080 y=1002=50 3=4=50 ABC=2+4=40+50=90and ADC=1+3=70+50=120 angles are 70,90,80,120.


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