Find the angular impulse applied to the particle in the 4 sec.
A
10kg-m2/sec
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B
40kg-m2/sec
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C
20kg-m2/sec
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D
5kg-m2/sec
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Solution
The correct option is C20kg-m2/sec From the fundamental equation: τ=dLdt ∴ΔL=∫LfLidL=∫τdt ΔL=Change in angular momentum ∫τdt=Angular impulse ⇒Angular impulse applied to the particle in the time interval of 4s is given by area under torque-time i.e (τ−t) graph. Angular impulse (J) = Area of triangle ABC =12×4×10 =20kg-m2/sec