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Question

Find the angular impulse applied to the particle in the 4 sec.


A
10 kg-m2/sec
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B
40 kg-m2/sec
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C
20 kg-m2/sec
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D
5 kg-m2/sec
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Solution

The correct option is C 20 kg-m2/sec
From the fundamental equation:
τ=dLdt
ΔL=LfLidL=τdt
ΔL=Change in angular momentum
τdt=Angular impulse
Angular impulse applied to the particle in the time interval of 4 s is given by area under torque-time i.e (τt) graph.
Angular impulse (J) = Area of triangle ABC
=12×4×10
=20 kg-m2/sec

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