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Newton's Second Law: Rotatory Version

Find the angu...

Question

Find the angular momentum of particle of mass 1 mg revolving about a circle of radius 30 cm with the speed of 1km/s.

2 x 10^{- 6} k g m^{2} / s

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0.3 k g m^{2} / s

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2 \times 10^{5} k g m^{2} / s

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3 \times 10^{- 4} k g m^{2} / s

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Solution

The correct option is A $0.3 k g m^{2} / s$
Angular Momentum = $m v r$
$= 1 \times 10^{- 3} \times 1000 \times 0.3 = 0.3 k g m^{2} / s$

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