i. antilog(2.7523)
This means logarithm of some number x is 2.7523.
Here the characteristic is 2.
The mantissa of 2.7523 is positive and is equal to 0.7523.
Now, look into the row starting 0.75. In this row, look at number in the column headed by 2. The number is 5649.
Now in the same row move in the column of mean differences and look at the number in the column headed by 3. The number there is 4.
Add this number to 5649, we get 5653.
Since, the characteristic is 2. So the decimal point is put after three digits, we get 565.3.
Hence, antilog(2.7523)=565.3
ii. antilog(3.7523)
Here, the characteristic is 3
The mantissa of 3.7523 is the same as the mantissa of the number in step (i) i.e 5653
The decimal point is put after four digits, we get 5653.0.
Hence, antilog(3.7523)=5653.0
iii. antilog(5.7523)
Here, the characteristic is 5.
The mantissa of 5.7523 is the same as the mantissa of the number in step (i) i.e. 5653
The decimal point is put after six digits, we get 565300.0
Hence, antilog(5.7523)=565300.0
iv. antilog(0.7523)
Here, the characteristic is 0.
The mantissa of 0.7523 is the same as the mantissa of the number in step (i) i.e. 5653
The decimal point is put after 1 digit, we get 5.653
Hence, antilog(0.7523)=5.653.
v. antilog(¯1.7523)
In this case, the characteristic is ¯1, i.e. -1.
The mantissa of 0.7523 is the same as the mantissa of the number in step (i) i.e. 5653
Since, the characteristic is negative 1, the decimal point is to be moved in right (−1+1=0) digit, we get 0.5653
Hence, antilog(¯1.7523)=0.5653
vi. antilog(¯2.7523)
In this case, the characteristic is ¯2, i.e. −2.
The mantissa of 0.7523 is the same as the mantissa of the number in step (i) i.e. 5653
In this, case, the characteristic is ¯2, i.e.-2, the decimal point is to be moved in one digit (−2+1=−1) in right .
So, we write one zero on the right side of the decimal point.
Hence, antilog(¯2.7523)=0.05653
vii. antilog(¯3.7523)
In this case, the characteristic is ¯3, i.e. -3.
The mantissa of 0.7523 is the same as the mantissa of the number in step (i) i.e. 5653
In this, case, the characteristic is ¯3, i.e.-3, the decimal point is to be moved in 2 digits (−3+1=−2) in right .
So, we write 2 zeros on the right side of the decimal point.
Hence, antilog(¯3.7523)=0.005653.