Find the approximate average percentage of marks obtained by all the students in English.

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None of these

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Solution

The correct option is B 63
Total marks obtained by all students in English
$= 86 + 97 + 115 + 68 + 118 + 86 = 570$
Required percentage
$= \frac{570}{900} \times 100 = \frac{570}{9} = 63.3 % \approx 63 %$

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What is the difference between the percentage marks obtained by student C in English and the average percentage marks of all the six subjects?

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