Find the approximate length of the hypotenuse.

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Solution

Using Pythagoras Theorem,
we get,
$x^{2} = (19.7)^{2} + (13.7)^{2}$
$x^{2} = 388.09 + 187.69 = 575.78 u n i t s^{2}$
$∴ x = \sqrt{575.78} = 23.995 u n i t s .$
$∴ x = 24 units (approx)$

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Find the approximate length of the hypotenuse.

Using Pythagoras Theorem, we get, x2=(19.7)2+(13.7)2 x2=388.09+187.69=575.78 units2 ∴x=√575.78=23.995 units. ∴x=24 units (approx)

Using Pythagoras Theorem,
we get,
$x^{2} = (19.7)^{2} + (13.7)^{2}$
$x^{2} = 388.09 + 187.69 = 575.78 u n i t s^{2}$
$∴ x = \sqrt{575.78} = 23.995 u n i t s .$
$∴ x = 24 units (approx)$