Question

Find the approximate size of the nucleus of Nickel.
(Mass number = 59 Atomic number = 28)

• A. 3 fm
• B. 4 fm
• C. 2 fm
• D. 5 fm

Answer 1

The correct option is D 5 fm

We know, size of the nucleus is calculated as:
R = $\left(R_0\right)(Massnumber{)}^{1/3}$
where $R_0$ = 1.3 fermi
R is the radius of the nucleus
Mass number of nickel = 59
R = 1.3 $(59{)}^{1/3}$ fm
On solving, we get R = 5 fm