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Question

Find the approximate value of
2x3+3x25x+7 at x=2.05

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Solution

2x3+3x25x+7
=2(2.05)3+3(2.05)25(2.05)+7
=2×8.6+3×4.210.25+7
=17.2+12.610.25+7
=36.810.25
=26.55
=27

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