wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Find the approximate value of mode for the following data:


Marks
5060
6070
7080
8090
90100
Students
12
10
24
5
9


A
71
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
72
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
74
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 74

Here the frequency of class interval 7080 is the maximum.

So, it is the modal class

Now

l = lower limit of modal class =70

f1= frequency of modal class =24

f0= frequency of class preceding the modal class =10

f2= frequency of class succeeding the modal class =5

h=class interval width =10


Mode =l+(f1f02f1f0f2)×h

=70+(24102×24105)×10

=70+(144815)×10

=70+4.24

=74.24

Mode 74


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mode
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon