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Question

Find the approximate value of sin1(0.51) given that 3=1.7321

A
π6+0.011541
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B
π3+0.011541
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C
π6+0.011547
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D
π3+0.011547
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Solution

The correct option is A π6+0.011541
sin1(0.5+0.01)=sin1(0.51)
Approx value=f(x)+hf(x)
Here x=0.5
h=0.01
f(u)=sin1x
f(u)=11x2
f(0.5)=sin1(0.5)=π6
f(0.5)=11(0.5)2
=10.75
=23
Approx value =π6+23×(1100)
π6+21003
=π6+0.011541


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