Question

Find the approximate value of $\sqrt{5245}$.

• A. 70.5
• B. 72.3
• C. 71.8
• D. 79.2

Answer 1

Answer: (B)

72.3

${72}^2$ = 5184
${73}^2$ = 5329
In between this two squares, 5245 is placed.
So average of $\frac{72+73}{2}=72.5$
Then, ${72.5}^2=5256.25$
So, $\sqrt{5245}\approx 72.3$