Question

Find the area and perimeter of a rhombus if its diagonals are $12cm,16cm$ and its side is $10cm$.

Answer 1

Given,
Diagonals of rhombus $=12cm,16cm$

Side of rhombus $=10cm$

$\begin{array}{cc}\text{Area of rhombus}& =\frac{\text{diagonal 1}\times \text{diagonal 2}}{2}\\ & =\frac{12\times 16}{2}\\ & =\frac{192}{2}\\ & =96c{m}^2\end{array}$

$\begin{array}{cc}\text{Perimter of rhombus}& =4\times \text{side}\\ & =4\times 10\\ & =40cm\end{array}$