Question

Find the area and perimeter of an isosceles right triangle, each of whose equal sides measures 10 cm. [Take $\sqrt{2}$ = 1.41.]

Answer 1

If it is an isosceles right triangle, all that means is that the two smaller angles are congruent and the two legs are congruent. So, you can flip the triangle on its side so that the base is one of the legs that are 10 cm. Then, the base of the triangle is 10 cm and the height is also 10 cm. Now we can easily find the area:

$Area=\frac{1}{2}\times b\times h$

$=\frac{1}{2}\times (10\times 10)=\frac{1}{2}\times 100=50$

Therefore, the area of the triangle is 50 $c{m}^2$